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(Leetcode) Find First and Last Position of Element in Sorted Array.cpp
Views: 1 | Author: cody
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 | class Solution { public: vector<int> searchRange(vector<int>& nums, int target) { int n = nums.size(); if(n==0)return {-1,-1}; //First Binary search to find first true for the condition nums[m] >= target int l = 0, h = n-1; while(l<h){ int m = l + (h-l)/2; if(nums[m]>=target){ h = m; } else{ l = m+1; } } if(nums[l]!=target) return {-1,-1};//To check either target is present or not int startIndex = l ; //Second binary search to find last false for the condition nums[m]>target l = 0; h = n-1; while(l<h){ int m = l + (h-l+1)/2; if(nums[m]>target){ h = m; } else{ l = m-1; } } int endIndex = l; return {startIndex,endIndex}; } }; |